Question

What is the x-intercept and y-intercept of the graph of 3x - 4y = 12?

x-intercept = (-4, 0); y-intercept = (0, 3)

x-intercept = (4, 0); y-intercept = (0, -3)

x-intercept = (0, -3); y-intercept = (4, 0)

x-intercept = (0, 3); y-intercept = (-4, 0)

Answer 1

3x - 4y = 12
3x - 4y -12 =0
x-int = -c/a = -[(-12)/(3)] = 4
y-int = -c/b = -[(-12)/(-4)] = -3
therefore x-int = (4,0), y-int = (0, -3)

Answer 2

thanks

Answer 3

welcome :)