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Mathematics 7 Online
OpenStudy (anonymous):

|x + 3| < 5

OpenStudy (anonymous):

|x|=x when x>0 |x|=-x when x<0

OpenStudy (anonymous):

the answer is 0 ?

OpenStudy (anonymous):

hence|x|<2 |x|<a -a<x<a will be the solution so in here -2<x<2

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