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Solve to find X. >>> x+2=sqrt(7+2x)
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x+2=sqrt(7+2x) square both sides: (x + 2)^2 = 7 + 2x x^2 + 4x + 4 = 7 + 2x x^2 + 2x - 3 = 0 do you know what to do from here?
ummmm.... not really. could you explain then i could try ..
subtract 2x and -3?
ok, factor that left side of x^2 + 2x - 3 = 0:
(x+3)(x-1)
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yes... now the solution is obviously x = -3 or x = 1. But remember to always check these solutions by sticking your solutions back into the ORIGINAL equation. What's the solution?
okkkk OMG thank youuu soo much.
way to go! you're welcome.
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