Question

Solve the equation. Check for extraneous solutions.

1) square root of x+7 = x+1

Answer 1

\[\sqrt{x+7}=x+1\]

Answer 2

\[\sqrt{x + 7} = x + 1\]
squaring both sides u get
\[x+7 = (x + 1)^{2}\]
this gives\[x + 7 = x ^{2} + 2x + 1\]

now u just have to simplify and solve the resulting quadratic equation for x...
if u need help, let me know

Answer 3

I already tried doing that and i got x= -3, 2
but when i plug it in it doesn't work

Answer 4

we get\[x ^{2} + x - 6 = 0\]
x^2 + 3x - 2x - 6 = 0
x(x + 3) -2(x + 3) = 0
(x -2)(x + 3) = 0
so
x = 2 or x = -3

and both are right

I'll show thru drawing..