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Mathematics 14 Online
OpenStudy (anonymous):

Evaluate the indefinite integral of: [(cosx)^2/(sinx)]dx I would like a hint, not the answer please.

OpenStudy (anonymous):

let u=sin(x)

OpenStudy (anonymous):

now the answer is....

OpenStudy (anonymous):

No that would not work.

OpenStudy (anonymous):

it is (cosx)^2

OpenStudy (anonymous):

Take u=cos^x

OpenStudy (anonymous):

right, which is actually cos^2(x)

OpenStudy (anonymous):

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