Question

Evaluate the integral: 3/square root(4-9x^2)dx

Answer 1

Same, use \[x=asin \theta\]

Answer 2

\[\int\limits\frac{3}{\sqrt{4-9x^{2}}} dx => 3\int\limits\frac{1}{\sqrt{4-9x^{2}}} =>3\int\limits\frac{1}{\sqrt{9(\frac{4}{9}-x^{2})}} \]
It's a trig inverse function..