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How much pure antifreeze must be added to 12 L of a 40% solution to obtain a 60% solution. (Remember that pure antifreeze is 100% = 1.) What is the correct question to solve this problem? A. 0.4(12) + 1(x) = 0.6(12 + x) B. 0.4x + 1(12) = 0.6(12 + x) C. 0.6(12) + 1(x) = 0.4(12 + x) D. 0.6x + 1(12) = 0.4(12 + x)
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