Question

Identify the vertex and the y-intercept of the given parabola: y=-3(x+2)^2+5

Answer 1

y=-3(x^2 +2x +4) +5
y=-3x^2 -6x -12 +5
y= -3x^2 -6x -7

Answer 2

@jhonyy9 , they asked for vertex. not the solutions/

Answer 3

I figured out the vertex, I just don't know the y-solution. It's either -7 or 7. I'm not sure though.

Answer 4

y=-3(x+2)^2+5

In this problem,

The vertex is (-2, 5)
We found this as we have to change the sign for the term with "x" and we write the outside co-efficent as it is.

For y-intercpet, make x = 0

-3(0 + 2)^2 + 5
-3(2)^2 + 5
-3(4) + 5
-12 + 5
-7

Answer 5

Ah thank you so much!!!!! :)

Answer 6

No problem! :)