Question

Write the equation of the parabola in vertex form:
Vertex: (0,3) that goes through the point (-4,-45)

Answer 1

Equation of a parabola with vertex (h,k)
\[y=a(x-h)^2+k\]
here vertex is (0, 3)
so
\[y=a(x)^2+3\]
Now we need to find a, it's given that the parabola passes through(-4, -45) . Substitute x=-4 and y=-45
\[-45=a(-4)^2+3\]
subtract 3 from both sides
\[-48=a(16)\]
Divid both sides by 16
\[-3=a\]
So a=-3, The equation of parabola with vertex (0,3) is
\[y=-3(x)^2+3\]

Answer 2

Thanks so much ash! :)

Answer 3

@Welcome Anna

Answer 4

The part easily missed is "a" :
y = a( x -h)^2 + k