Question

c=5/9(14-32)

Answer 1

We have
\[\huge c= \frac{5}{9}(14-32)\]
Let's simplify the bracket first
\[\huge c= \frac{5}{9} \times (-18)\]
now
\[\huge c= \frac{5}{\cancel 9} \times -(\cancel{18} 2)\]
we have now
\[\huge c= 5\times (-2)\]
we get
\[\huge c=-10\]

Answer 2

ohh ok i get it now thank you

Answer 3

@yay1234 Welcome:D