Question

The length of a rectangle is 3 yd more than twice its width, and the area of the rectangle is 35 yd^2 . Find the dimensions of the rectangle.

Answer 1

let the width be x

then the length is 2x + 3

then the area is

x(2x+3) = 35

2x^2 + 3x - 35 = 0

solve the quadratic and only consider the positive solution.