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Is this correct? (Basic logs) 3^(x+2) = 5^(x-1) (x+2)log(3) = (x-1)log(5) x+2=(x-1)*((log(5))/(log(3))) x+2=1.46x-1.46 3.46=0.46x x=7.52
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i got 7.452 but i guess its a rounding thing. id say you are correct :)
Thanks :D
no prob man ;)
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