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3lnx-ln(x+1)=ln(x-1) Solve for x
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ln(x^3/(x+1))=ln(x-1)
x^3/(x+1)=(x-1)
x^3=x^2-1
x^3-x^2+1=0
hmm im lost now..
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Solve with quadratic formula?
not a quadratic...
Oh wow i'm an idiot.
It's not quadratic. If there are any rational roots they are factors of 1. So use synthetic division with 1 and/or -1 on the "shelf" and see if either is a root.
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