Question

write a slope-intercept equation for the line that passes through (-8,-11) and is perpendicular to -2x-7y=-14

Answer 1

-2x-7y=-14
y=(-2/7)x+2

let s=gradient of y=-2/7
let t=gradient of line that passes through (-8,-11) and is perpendicular to -2x-7y=-14

s*t=-1
(-2/7)*t=-1
t=7/2

Y=tX+C , (-8,-11)
-11=(7/2)(-11) + C
C=55/2

Y=(7/2)X+ 55/2