Arithmetic Sequence: Given the first element 19/7 and the common difference -2/7 and the Sn(arithmetic series) 13. Find the value of the nth element and the value of N
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OpenStudy (anonymous):
\[a _{1}=19/7\]
OpenStudy (anonymous):
\[\huge s _{n}=13\]
OpenStudy (anonymous):
\[\huge a _{n}\] is the nth element.
OpenStudy (anonymous):
what do u think?
OpenStudy (anonymous):
formulas: \[\huge s _{n}=(N/2)(a _{1}+a _{n})\]
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OpenStudy (anonymous):
\[\huge a _{n}= a _{1} + (N-1)d\]
OpenStudy (anonymous):
u had to find nth element so will apply this formula \[_{Sn}=n/2(2a+(n-1)d)\]
OpenStudy (anonymous):
ok. then what? :(
OpenStudy (anonymous):
this is part of our quiz and i didnt get the correct answer. thats why im asking for help because our exam is tomorrow
OpenStudy (anonymous):
then after u will get a quadratic equation in terms of n. So u had solve for n.
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OpenStudy (anonymous):
\[(−34N2+490N−3094)/119\]
OpenStudy (anonymous):
\[n^{2}-20n+91\] will get this equation
OpenStudy (anonymous):
how did you get that? :((
OpenStudy (anonymous):
please show me the soln. :(
OpenStudy (anonymous):
oh. shoot.i wrote something wrong in the given. a sub 1 should be equal to 19/17
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