What I actuallly wanted to ask with my previous question:
"Shadow generating function" applied to cubics. y1=(x+2)(x-(3+2i))(x-(3-2i))
y2=(x+2)(x-(3+2))(x-(3-2))
What are the points of intersection?
I get x1=3 x2=3 which makes no sense with the graph... I must be doing something wrong.

Question

What I actuallly wanted to ask with my previous question: 
"Shadow generating function" applied to cubics. y1=(x+2)(x-(3+2i))(x-(3-2i))
y2=(x+2)(x-(3+2))(x-(3-2))
What are the points of intersection? 
I get x1=3 x2=3 which makes no sense with the graph... I must be doing something wrong.

anonymous · Answer

Is i^2= -1 or is it a variable?

anonymous · Answer

i^2=-1

anonymous · Answer

http://www.wolframalpha.com/input/?i=+y1%3D%28x%2B2%29%28x-%283%2B2i%29%29%28x-%283-2i%29%29 http://www.wolframalpha.com/input/?i=y2%3D%28x%2B2%29%28x-%283%2B2%29%29%28x-%283-2%29%29

anonymous · Answer

Compare the graphs.

anonymous · Answer

ah no thats not y^2 its like g(x). 
I meant y1 as f(x) and y2 as g(x). sorry.