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e^x-4=e^-x (Solve) I came up with 0
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u mean e^(x-4) = e^(-x) ?.
x=-2
I don't get 0 as the answer. \[e^{x-4}=e^{-x}\]\[\frac{e^{x-4}}{e^{-x}}=1\]\[e^{2x-4}=e^{0}\]\[2x-4=0\]\[2x=4\]\[x=2\]
How have you gone about solving the question koons4?
I must of not finished it out, because I only got 2x-4=0 That is where I think I messed up.
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No worries, good luck :)
Trust me I need it!
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