Question

f(x)=(x+2)(x-(3+2i))(x-(3-2i)
g(x)=(x+2)(x-(3+2))(x-(3-2))
The points of intersection are (-2,0) and (3,20), how do I prove this?

Answer 1

I would actually just plug in x value for both f(x) and g(x) and see if they solute to 0
then plug x = 3 for both and see if they solute to 20