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Solve the following inequality and graph the solution set |x+8|>3
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\[(-\infty,11) \upsilon (-5,\infty) \]
I think thats the answer
you have the right idea but the wrong answer
\[|x+8|>3\implies x+8<-3 \text{ or } x+8>3\]
\[x+8<-3\] \[x<-11\] or \[x+8>3\] \[x>-5\] so solution is \[(-\infty, -11)\cup (-5,\infty)\]
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