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Solve √(9x+81)=x+5 The solution is x=
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is it -8,7 and do I put parenthesis around them
Square both sides:\[9x+81 = (x+5)^{2}\]\[9x+81 = x^{2}+10x+25\]Get everything on one side:\[0 = x^{2}+x-56\]Factor:\[0 = (x-7)(x+8)\]So x is 7 or -8
x=7
7(9)+81=63+81=144 7+5=12 7 works ------ 9(-8)+81=9 -8+5=-3 -8 doesn't work ------- :) Great work!
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