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Mathematics 20 Online
OpenStudy (anonymous):

Arrange the following functions in increasing order of growth rate: a)2^2^n b)2^n^2 c)n^2^n

OpenStudy (anonymous):

a, b, c. I'm fairly sure about this, but i'm not a bible.... :P

OpenStudy (anonymous):

ok, then 2^n log(n) > n^2^n, no?

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