Question

Circle A has an equation of x2 + (y + 3)2 = 16. Where is the center of the circle located?

Answer 1

\[(x-h)^2+(y-k)^2=r^2\] has center (h,k) radius r

Answer 2

you have
\[(x-0)^2+(y-(-3))^2=4^2\] so center is
\[(0,-3)\] radius if 4

Answer 3

x^2+6y=16