Question

a cell supplies a current of 2.2amp through 2ohm resistors when connected in parallel.when same resistors r connected in series it supplies a current of 0.4amp..find emf and internal resistance of the cell

Answer 1

how many 2 ohm resistor are there?

Answer 2

2

Answer 3

Let the internal resistance and emf of the cell be R and E respectively.
when resistors are parallel then
I=E/Req=E*(1/2+1/2+1/R)=2.2......(1)
when resistors are in series then
I=E/Req=E/(2+2+R)=0.4............(11)
solve (1) and (11) and find the value of E and R.