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Given the triangle below, what is cot∡B?
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Cot=1/tan=adjacent/opposite
\[\sqrt{33}/7\] \[7\sqrt{33}/33\] \[4\sqrt{33}/33\] \[\sqrt{33}/4\]
Very short video http://www.khanacademy.org/math/trigonometry/v/basic-trigonometry explains sin, cos, and tan once you know them, learn csc= 1/sin , sec= 1/cos , cot= 1/tan To answer your question, at angle B, label the adjacent side, and the opposite side. then write down the ratio adjacent/opposite (of course, you need to use pythagoras to figure out the length of the unknown side)
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