Question

Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth
x² + 3 = –4x

Answer 1

x^(2)+3=-4x

x^(2)+4x+3=0
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a=1 b=4 c=3
\[\huge x=\frac{-b \pm \sqrt{b ^{2}-4ac}}{2a}\]
\[\huge x=\frac{-(4) \pm \sqrt{16-4(3)}}{2}\]
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\[\huge x=\frac{-(4)+2}{2}\] OR
\[\huge x=\frac{-(4)-2}{2}\]
x=-3,-1