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write the slope-intercept form of the equation of the line described (0,5), perp. to y=-2/5x+2
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perpendicular, \[m_1m_2=-1\] \[-2/5 m_2=-1\] \[m_2=5/2\] \[y-y_1=m(x-x_1)\] y-5=5/2(x-0) y=5x/2 +5
thanks
I have one more
write the slope-intercept form of the equation of the line through the given point with the given slope (-1,1) slope =-6
y-y1=m(x-x1)
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wich is right above it.
y-1=(-6)(x--1) y=-6x-6+1 y=-6x-5
thanks so much
First question answer: y=5x/2 +5 Second question answer: y=-6x-5
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