Find the range if y = 3x + 12 for x = {0.4, 0.6, 1.8, 2.2}. A. {1.2, 1.8, 5.4, 6.6} B. {13.2, 13.8, 17.4, 18.6} C. {12.4, 12.6, 13.8, 14.2}
All you have to do here is plug those values in for x and choose the choice that matches up to the answers you get. i.e the first one is y=3(0.4)+12 1.2+12 13.2 With this being a multiple choice problem, that really should be enough to get your answer based on the choices you have, but it's always a good idea to go ahead and check them all to make sure all the domain inputs give you the listed range outputs.
So can you show me step by step and than show me the answer?
Well let's have you try the second one. The second value you have for x is 0.6 and your function is 3x+12 Try plugging 0.6 in for x and see what value you get. Hint: the values you were given for x, x = {0.4, 0.6, 1.8, 2.2} are your domain. The answers you get by plugging those numbers in are your range.
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So your function is y=3x+12 Your first input is 0.4 which I did for you. y=3(0.4)+12 see how I placed the 0.4 in place of x and then solved the problem? 3*0.4 is 1.2 1.2+12 is 13.2 So the first number in our range is 13.2 So if we take the same function 3x+12 and we replace x with 0.6, what do we get?
Or we could break it down a little more. What is 3*0.6?
1.8
And if we add 12 to that?
13.8
And that is the second number of our range. Now we have established the first two numbers so we have {13.2, 13.8, ?, ?} So we just need the final two. The next x value we have to work with is 1.8 What do we get when we plug that into 3x+12?
Well you narrowed it down, and i already have the answer. Thank you.
You're welcome.
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