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factoring i already factored but do not know what to do next i got 3x(n^4-7x^2) please help!
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what is the original problem?
3xn^4 - 27x^3
\[3n^4-27n^3\] is this your problem?
no 3xn to the 4
the inside is a difference of squares however it should be 3x(n^4 -9x^2) .....9*3 = 27
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\[3xn^4-27n^3\] this is it?
I think I will let dumbcow solve this one.....
a^2 - b^2 = (a+b)(a-b) --> n^4-9x^2 = (n^2 +3x)(n^2 -3x)
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