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identify the vertex and the axis of symmetry for the graph of y=-5(x-2)^2+4
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Vertex (2,4) Axis of symmetry =2
how did you find the axis of symmetry?
From your equation y=-5(x-2)^2+4 (x-2)=0 x=2
The vertex form of a quadratic is given by y = a(x – h)2 + k, where (h, k) is the vertex.
okay thankyou :)
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yw
You might find this site useful if you want to understand this further: http://www.mathwarehouse.com/geometry/parabola/standard-and-vertex-form.php
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