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solve x^3-64=0
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x^3 = 64 x = 64^1/3 x = (4)^3/3 = 4
im sorry i meant factor then solve. thanks
It is the same: (x^3 - 4^3) = 0 a^3 - b^3 = (a – b)(a2 + ab + b2) So, you get: (x-4)(x^2 + 4x + 16) = 0 x=4. Other factor produces imaginary roots.
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