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Find f. f''(theta)=sin(theta)+cos(theta) f(0)=2 f'(0)=2 I've tried it and got f=-sin(theta)-cos(theta)+(3x^2)/2 but it was wrong :/ help please?
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I think this works: f(x) = -sinx - cosx + 3x + 3.
no it didnt :/
Let's check: |dw:1332221971884:dw|
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