Question

What is the equation of the line in slope-intercept form that passes through the point (3, –5) and is perpendicular to the line y = 3x – 6?

Answer 1

y+5 = -1/3*(x-3)

Answer 2

any line perp to a given line
then m1*m2=-1
m1=slope of known line
m2=slope of unknown line
then find slope and put it in
y-y1=m(x-x1)

Answer 3

Here are the choices
y = –3x – 4

y = –3x + 4

y = x – 4

y = x + 4

Answer 4

try it yourself i gave you the hint!!!!