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(2x^2+3x+1)/(2x+1) Using complete sentences, explain why f(1) = 2, f(0) = 1, and f(–1) = 0, yet f(–) is undefined. Make sure to show your work.
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yet f(-1/2) is undefined **
because when x = -1/2, the denominator will be 0... how do you divide by zero?
ok and you have to simplify the f(x) = (2x^2+3x+1)/(2x+1)
and show your work ..
simplified, f(x) = x+1. Just factor the top to (2x+1)(x+1).
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restriction?
x is not equal to -1/2
can you help me on my other question
sure
Show all work in dividing: y^2+5y-6/y^2-3y-10 by y^2+2y-3/y^2-4y-5. Use complete sentences to explain how to simplify this expression
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factor. |dw:1332264293924:dw|
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