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Mathematics 22 Online
OpenStudy (anonymous):

A circle is shown on the coordinate plane below. What is the equation of this circle? x2 + (y + 1)2 = 4 x2 + (y – 1)2 = 2 x2 + (y + 1)2 = 2 x2 + (y – 1)2 = 4

OpenStudy (anonymous):

OpenStudy (hoblos):

it is of center (0,1) and radius 2

OpenStudy (hoblos):

so the equation would be x2 + (y – 1)2 = 4

OpenStudy (anonymous):

thanks

OpenStudy (hoblos):

yw :)

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