Alphasia headed for the rodeo at 9 am at 30 mph. At 11 am bubba headed after her at 60 mph. What time was it when Bubba caught Alphasia?

Question

anonymous · Answer

hello?

mysesshou · Answer

Assuming they started same place...
Distance = Rate*Time    
Alphasia_distance = Bubba_distance

Alph has 2 hours ahead of bubba, so Alph is 60 miles ahead of bubba when bubba starts.

solve for the time
60mi + (30mi/h)*time = (60mi/h)*time
60mi = (30mi/h)*time
time = 60mi/(30mi/hr) = 2 hr

Then to check, Alph initial 2 hours gives 60miles, plus 2 more hours = 60 more miles, totaling 120miles.
Bubba given 2hours is 60mph*2hr = 120 miles.

so they both travel 120 miles.  
Alph travels from 9am until 1pm
Bubba travels from 11am - 1pm

they meet up at 1pm.

I think it is right,  hopefully someone proofs this    :)

mysesshou · Answer

sorry, was typing and checking my work..   :)

anonymous · Answer

cool

anonymous · Answer

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