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Find vertex and focus y^2=-6X can someone jus tell me how to find both :]
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0,0 is the vertex
focus is (-3/2,0)
Yes... V(0,0) and F(-3/2,0)
......... How to find focus.....
As this is a parobola which is opening towards left so the formula of its focus is F(-a,0)
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I dont get it what is A..?
to find a we have to compare the question with the general left sided open parabola which is y^2=-(4a)x
in the given question 4a is given
from the question 4a=6 so, a=3/2
got it or not?
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Yess i didnt know the regular equation for one that is why that you!
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