Question

please can anyone help me with a computer science (c++) problem.......Write a program that reads from the user a letter, and prints out the digit value corresponding to this letter based on the encoding on a mobile phone's keypad. For example, for a, b, or c, the program would print the digit 1. If the letter entered is not one of the letters of the alphabet, print a value of -1. Use a switch statement

Answer 1

easyyy....... but i rly don't feel like doing this hahah

Answer 2

haha :0

Answer 3

:)

Answer 4

i'm still new to the c++ thing so i really need help

Answer 5

just do:
cout << "Please enter a letter";
cin >> a;
then switch case.. like case a, b, or c display this.. very simple hold on..

Answer 6

tyt

Answer 7

writing in the compiler.. give me a few mins

Answer 8

its ok take your time, really appreciate your help

Answer 9

wait what corresponds to what again? like isn't abc on 2, so shouldn't it be 2, not 1?

Answer 10

oh you're right..

Answer 11

it's 2 then

Answer 12

#include <iostream>

using namespace std;

int main()
{
char letter;
cout << "Please enter a letter: ";
cin >> letter;

switch (letter)
{
case 'a':
cout << "\n2\n" << endl;
break;

case 'b':
cout << "\n2\n" << endl;
break;

case 'c':
cout << "\n2\n" << endl;
break;

case 'd':
cout << "\n3\n" << endl;
break;

case 'e':
cout << "\n3\n" << endl;
break;

case 'f':
cout << "\n3\n" << endl;
break;

case 'g':
cout << "\n4\n" << endl;
break;

case 'h':
cout << "\n4\n" << endl;
break;

case 'i':
cout << "\n4\n" << endl;
break;

case 'j':
cout << "\n5\n" << endl;
break;

case 'k':
cout << "\n5\n" << endl;
break;

case 'l':
cout << "\n5\n" << endl;
break;

case 'm':
cout << "\n6\n" << endl;
break;

case 'n':
cout << "\n6\n" << endl;
break;

case 'o':
cout << "\n6\n" << endl;
break;

case 'p':
cout << "\n7\n" << endl;
break;

case 'q':
cout << "\n7\n" << endl;
break;

case 'r':
cout << "\n7\n" << endl;
break;

case 's':
cout << "\n7\n" << endl;
break;

case 't':
cout << "\n8\n" << endl;
break;

case 'u':
cout << "\n8\n" << endl;
break;

case 'v':
cout << "\n8\n" << endl;
break;

case 'w':
cout << "\n9\n" << endl;
break;

case 'x':
cout << "\n9\n" << endl;
break;

case 'y':
cout << "\n9\n" << endl;
break;

case 'z':
cout << "\n9\n" << endl;
break;

default:
cout << "\n-1\n" << endl;
}

system("pause");
return 0;
}

Answer 13

it worked, you're the best
thank you so much , really appreciate what've done,and sorry it took a lot of time

Answer 14

nah it wasn't that hard hahah np

Answer 15

thanks :)