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Find the average rate of change of the function f over the given interval. f(x)=0.25x^4-x^2-9x+8 from x=-4 to x=3
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\[\frac{f(-4)-f(3)}{-4-3}\] Use this to find the slope of the secant line from x=-4 to x=3
I don't understand how you put that into the problem.
No you put the problem into that
Do you know how to find f(-4)?
Would you put it into the equation?
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Replace the x's in your function with -4's
Then to evaluate f(3) Replace the x's in your function with 3's
So what I got is for f(-4)= 92 and f(3)= -7.75...is that right?
That is right ! :)
\[\frac{92-(-7.75)}{-4-3}\]
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Ooooh wow I get it now! Thank you so much!
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