Question

What are the approximate solutions of 4x^2 + 3 = −12x to the nearest hundredth?

Answer 1

\[4x^2+12x+3=0\]
solve using quadratic equation

\[x=\frac{-b \pm \sqrt(b^2-4*a*c)}{2*a}\]

Plug into calculator: \[x=\frac{-12 \pm \sqrt(12^2-4*4*3)}{2*4}\]


http://www.wolframalpha.com/input/?i=solve+4x2%2B12x%2B3%3D0

Answer 2

http://www.wolframalpha.com/input/?i=solve+%28-12+%2B+sqrt%2812%5E2-4*4*3%29%29%2F%282*4%29

Answer 3

this is the other solution, for -b - sqrt()....
http://www.wolframalpha.com/input/?i=solve+%28-12+-+sqrt%2812%5E2-4*4*3%29%29%2F%282*4%29