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Mathematics 20 Online
OpenStudy (anonymous):

How do I solve this? x(x-6) - (x-6)(x-2)

OpenStudy (anonymous):

as in "factor"?

OpenStudy (anonymous):

x=6

OpenStudy (anonymous):

you have a common factor of (x-6) in each term, so it is \[(x-6)(x-(x-2))\] \[(x-6)\times 2\] or \[2(x-6)\]

OpenStudy (anonymous):

thanks :)

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