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how do you write an equation fot the line passing through (-3,5) and (-1,5) and find both intercepts x and y
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why not first try to find the slope of the line. \[(y_2-y_1)/(x_2-x_1)\]
use double point fomula y-y1 = ((y2-y1)/(x2-x1))*(x - x1) to find intercepts, for x, put y=0 in equation and find the value of x, that is your x intercept for y, put x=0 likewise
i thought to find the slope it was y-y1/x-x1
what did you get with that equation?
ok i figured that out.thanks
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