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r^3 - 4r +3 =0, factor this equation
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\[r^{3}-4r +3=0\]
\[(r-1) \left(r^2+r-3\right)=0 \]
can you do a step by step?
Do you know synthetic division and the rational roots theorem?
The following might help. http://www.youtube.com/watch?v=mXdAiJY7YfY I used the Mathematica program for this problem.
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forgot a zero here for a place holder for the r^2 term. that factorization is not right |dw:1332313870539:dw|
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