Question

lim x->-inf 1/2^x is the answer inf?

Answer 1

no it's still 0

Answer 2

how come lim x-> -inf e^-x is inf

Answer 3

because in your case u're blowing up the denominator of a fraction... and the bigger it gets, the smaller the fraction gets.. but e^(-x) as x goes to -inf is e^(-(-inf))=e^inf=inf

Answer 4

I have just put this limit(1/2^x, x = -infinity) in maple and the answer has come infinity

Answer 5

http://www.numberempire.com/limitcalculator.php