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OpenStudy (anonymous):
if f(x)= (1+x)(1+2x)(1+3x)...(1+nx) find f'(0)
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OpenStudy (anonymous):
f'(0) = 1+ 2 + 3+...+ n
OpenStudy (experimentx):
f'(x) = (1+2x)(1+3x)...(1+nx)+2*(1+x)(1+3x)..(1+nx)+3*(1+x)(1+2x)...(1+nx)
OpenStudy (experimentx):
the rest is myko's
OpenStudy (anonymous):
:)
OpenStudy (experimentx):
oops ... forgot to add ...+n*(1+x)(1+2x) .... (1+(n-1)x)
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