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Find the real solutions of the equation: 6+√(2x-9)=x
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\[6+\sqrt{2x-9}=x \implies \sqrt{2x-9}=x-6\]\[\implies 2x-9=x^2-12x+36 \implies 0=x^2-10x+45\]
That ought to get you close enough to solve it yourself. Don't forget to check your answers to make sure they work.
Could you give me the answer I'm stuck... Do I have to factor it?
Actually, there are no real solutions, since b^2-4ac=100-180<0.
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