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Which is a zero of the absolute value function f(x) = 1 - 3|3x5 - 4x2|?
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\[\large 0=1-3\left| 3x^5-4x^2 \right|\]\[\large \implies 3x^2\left( 3x^3-4 \right)=\pm1\] So, solve, \[\large 9x^5-12x^2-1=0\ and\ \large 9x^5-12x^2+1=0\]
solve if i solve this i will get my answer
yes ... *and should be or
http://www.wolframalpha.com/input/?i=9x%5E5-12x%5E2%2B1%3D0+or+9x%5E5-12x%5E2-1%3D0
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