Question

Given the linear equation y= -2/3x-2 find the y-coordinates of the points (-9, ), (-3, ), and (6, ). Please show all of your work

Answer 1

is this written \[y= -(2/3)x-2\]
or \[y= -2/(3x)-2\]

Answer 2

i'm assuming the first one?

Answer 3

\[y= -(2/3)*x-2\]
Substitute in the values of x into the equation:
\[y= -(2/3)*(-9)-2 = 6-2=4\]
\[y= -(2/3)*(-3)-2 = 2-2=0\]
\[y= -(2/3)*6-2 = -4-2=-6\]

y= -2/3x-2 find the y-coordinates of the points (-9, 4 ), (-3, 0 ), and (6, -6 ).
is what i get
:)

Answer 4

yes the x is on on the outside of the fraction