Given the linear equation y= -2/3x-2 find the y-coordinates of the points (-9, ), (-3, ), and (6, ). Please show all of your work

Question

Given the linear equation  y= -2/3x-2 find the y-coordinates of the points (-9,  ), (-3,  ), and (6,  ). Please show all of your work

mysesshou · Answer

is this written $$y= -(2/3)x-2$$
or $$y= -2/(3x)-2$$

mysesshou · Answer

i'm assuming the first one?

mysesshou · Answer

$$y= -(2/3)*x-2$$
Substitute in the values of x into the equation: 
$$y= -(2/3)*(-9)-2 = 6-2=4$$
$$y= -(2/3)*(-3)-2 = 2-2=0$$
$$y= -(2/3)*6-2 = -4-2=-6$$

y= -2/3x-2 find the y-coordinates of the points (-9, 4 ), (-3, 0 ), and (6, -6  ).
is what i get
:)

anonymous · Answer

yes the x is on on the outside of the fraction