Question

Differentiate (2*n*b^(r*x)+n)^k. In this question when it asks to differentiate, with respect to which variable should we differentiate this function?

Answer 1

\[(2nb^{rx}+n)^k\] is the equation that has to be differentiated

Answer 2

you mean find a derivative?

Answer 3

yes

Answer 4

if so; assume they are all functions of the same variable; and sort it out when you know more info :)

Answer 5

of course i got no idea how to recall to do an x^x type deal; but if you can remember it :) otherwise ill assume k to be constant
\[D(2nb^{rx}+n)^k=k(2nb^{rx}+n)^{(k-1)}*D(2nb^{rx}+n)\]
\[=k(2nb^{rx}+n)^{(k-1)}*(D(2nb^{rx})+D(n))\]
\[=k(2nb^{rx}+n)^{(k-1)}*(D(2nb^{rx})+n')\]
\[=k(2nb^{rx}+n)^{(k-1)}*(D(2n)b^{rx}+2nD(b^{rx})+n')\]
\[=k(2nb^{rx}+n)^{(k-1)}*(2n'b^{rx}+2nD(b^{rx})+n')\]
something similar to that is what id assume

Answer 6

Basically you have taken the derivative with respect to k

Answer 7

y = x^x

Ly = Lx^x

Ly = x Lx

y'/y = x' Lx+x L'x

y'/y = Lx+x/x

y'/y = Lx+1

y' = y(Lx+1)

y' = x^x (Lx+1)

y' = x^x Lx + x^x

might be what I was forgetting

Answer 8

well, I kept k constant and took the derivative of what I could with respect to say: time

Answer 9

\[(2(n(t))(b(t))^{(r(t)x(t))}+n(t))^k\]

somehting like this

Answer 10

but thats only becasue I have no idea what the question is in context really

Answer 11

The question just says differentiate. Thats it. Doesn't even ask with respect to which variable should the derivative be taken. Because the derivative changes with each variable

Answer 12

For example, if the derivative is taken with respect to x, the derivative of the function has a different answer... if it is taken with respect to n, the answer changes accordingly.

Answer 13

if we are to take partial derivaitves; meaning that all the variables are independant ... then yes

Answer 14

i was thinking more of an implicit version