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f(x)=(x+3)^2(x-1)^2 Need to find x and y intercept power function of f max # turning points behavior for x intercept 1 and -3
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to find x and y intercept, set x=0 and y=0, When x=0, y=(0+3)^2(0-1)^2 y=9 when y=0. x=1
To find power function of f, expand x^(2)-2x+1
Since its a quadratic, the graph has 1 turning point
So my pwer of f would be 1 right?
power function is 2, because x^(2)-2x+1 Observe the term with the greatest degree. x^2 Now, you know the power function is f(x) = x^2
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How do I fiqure out the behavior of the graph near x-intercept 1 and x-intercept -3?
x-intercept 1 and x-intercept -3 , means the curve touches the x axis 2 times, |dw:1332371340281:dw|
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