Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (anonymous):

secx/cscx +cscx/secx

OpenStudy (anonymous):

okay, what are the directions

OpenStudy (lgbasallote):

(secx/cscx) + (cscx/secx) right?

OpenStudy (mertsj):

\[\frac{sinx}{cosx}+\frac{cosx}{sinx}=\frac{\sin^2x+\cos^2x}{sinxcosx}=\frac{1}{sinxcosx}=cscxsecx\]

OpenStudy (anonymous):

its to simplify it

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Arriyanalol: i need help
2 days ago 7 Replies 1 Medal
Arriyanalol: CONGRATS to me
2 days ago 8 Replies 2 Medals
Legomaster346: What colleges are good that are near Arab Alabama?
1 week ago 5 Replies 0 Medals
Arriyanalol: i need help
1 week ago 6 Replies 2 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!