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Mathematics 7 Online
OpenStudy (anonymous):

secx/cscx +cscx/secx

OpenStudy (anonymous):

okay, what are the directions

OpenStudy (lgbasallote):

(secx/cscx) + (cscx/secx) right?

OpenStudy (mertsj):

\[\frac{sinx}{cosx}+\frac{cosx}{sinx}=\frac{\sin^2x+\cos^2x}{sinxcosx}=\frac{1}{sinxcosx}=cscxsecx\]

OpenStudy (anonymous):

its to simplify it

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